mirror of https://github.com/elk-zone/elk
61 lines
2.3 KiB
TypeScript
61 lines
2.3 KiB
TypeScript
import type { mastodon } from 'masto'
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const maxDistance = 10
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const maxSteps = 1000
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// Checks if (b) is a reply to (a)
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function areStatusesConsecutive(a: mastodon.v1.Status, b: mastodon.v1.Status) {
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const inReplyToId = b.inReplyToId ?? b.reblog?.inReplyToId
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return !!inReplyToId && (inReplyToId === a.reblog?.id || inReplyToId === a.id)
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}
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function removeFilteredItems(items: mastodon.v1.Status[], context: mastodon.v1.FilterContext): mastodon.v1.Status[] {
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const isStrict = (filter: mastodon.v1.FilterResult) => filter.filter.filterAction === 'hide' && filter.filter.context.includes(context)
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const isFiltered = (item: mastodon.v1.Status) => (item.account.id === currentUser.value?.account.id) || !item.filtered?.find(isStrict)
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const isReblogFiltered = (item: mastodon.v1.Status) => !item.reblog?.filtered?.find(isStrict)
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return [...items].filter(isFiltered).filter(isReblogFiltered)
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}
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export function reorderedTimeline(items: mastodon.v1.Status[], context: mastodon.v1.FilterContext = 'public') {
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let steps = 0
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const newItems = removeFilteredItems(items, context)
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for (let i = newItems.length - 1; i > 0; i--) {
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for (let k = 1; k <= maxDistance && i - k >= 0; k++) {
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// Prevent infinite loops
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steps++
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if (steps > maxSteps)
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return newItems
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// Check if the [i-k] item is a reply to the [i] item
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// This means that they are in the wrong order
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if (areStatusesConsecutive(newItems[i], newItems[i - k])) {
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const item = newItems.splice(i, 1)[0]
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newItems.splice(i - k, 0, item) // insert older item before the newer one
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k = 0
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}
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else if (k > 1) {
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// Check if the [i] item is a reply to the [i-k] item
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// This means that they are in the correct order but there are posts between them
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if (areStatusesConsecutive(newItems[i - k], newItems[i])) {
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// If the next statuses are already ordered, move them all
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let j = i
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for (; j < items.length - 1; j++) {
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if (!areStatusesConsecutive(newItems[j], newItems[j + 1]))
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break
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}
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const orderedCount = j - i + 1
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const itemsToMove = newItems.splice(i, orderedCount)
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// insert older item after the newer one
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newItems.splice(i - k + 1, 0, ...itemsToMove)
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k = 0
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}
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}
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}
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}
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return newItems
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}
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